What is the equation of the graph below? A graph shows a parabola that opens up and crosses the x axis at negative two and negative four.
Mathematics
kostismichael
Question
What is the equation of the graph below? A graph shows a parabola that opens up and crosses the x axis at negative two and negative four.
2 Answer

1. User Answers xavie2004
y = a(xh)2+k. (h,k) is the equation for the parabola
Plug the values in with the variables
You will get your right answer 
2. User Answers mreijepatmat
The function of a parabola is y= ax² + b x c
If x' = 2 & x" =  4 are the x intercepts then x=  2 & x"=  4 are the roots of this quadratic equation, we also know that this equation can be written as:
x²  Sx +P, where S= x' + x" (sum) & P = x' . x" (product), also we know (given) that x' = 2 & x" =  4, hence, plug fpr S & P
x²  (6) x + 8
===.> Y= X²+6X+8
& ITS AXIS OF SYMMETRY (b/2a) ===> x= 3.
a is positive so it passes by a minimum (open up) Minimum (3,1)