What are the factors of these two problems and how do you do the second one? 1. 32a^2 + 24b^2 2. 12a^2 –15ab –16a +20b
Advanced Placement (AP)
NotAProdigy
Question
What are the factors of these two problems and how do you do the second one?
1. 32a^2 + 24b^2
2. 12a^2 –15ab –16a +20b
1. 32a^2 + 24b^2
2. 12a^2 –15ab –16a +20b
1 Answer

1. User Answers mreijepatmat
12a² –15ab –16a +20b = (12a² –15ab) –(16a 20b)
1st parenthesis : (12a² –15ab) = 3a(4a  5b)
2nd parenthesis  (16a 20b) =  4(4a 5b)
1st + 2nd = 3a(4a  5b)  4(4a 5b)
common factor (4a5b) ==>hence (4a=5b)(3a4)