A 75kilogram bicyclist coasts down a hill at a constant speed of 12 meters per second. What is the kinetic energy of the bicyclist? (1) 4.5 × 10^2 J (3) 5.4 ×
Physics
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Question
A 75kilogram bicyclist coasts down a hill at a constant speed of 12 meters per second. What is the kinetic
energy of the bicyclist?
(1) 4.5 × 10^2 J (3) 5.4 × 10^3 J
(2) 9.0 × 10^2 J (4) 1.1 × 10^4 J
energy of the bicyclist?
(1) 4.5 × 10^2 J (3) 5.4 × 10^3 J
(2) 9.0 × 10^2 J (4) 1.1 × 10^4 J
2 Answer

1. User Answers TaylorBayley
Kinetic E=1/2mv^2
KE = 1/2 * 75 * 12^2 = 5400J = 5.4*10^3 J 
2. User Answers skyluke89
Answer:
(3) 5.4 × 10^3 J
Explanation:
The kinetic energy of the bicyclist can be calculated using the following equation:
[tex]K=\frac{1}{2}mv^2[/tex]
where
m = 75 kg is the mass of the bicyclist
v = 12 m/s is the speed of the byciclist
By substituting these numbers into the equation, we find:
[tex]K=\frac{1}{2}mv^2 = \frac{1}{2}(75 kg)(12 m/s)^2=5400 J=5.4 \cdot 10^3 J[/tex]
So, the correct answer is
(3) 5.4 × 10^3 J