Physics

Question

A 75-kilogram bicyclist coasts down a hill at a constant speed of 12 meters per second. What is the kinetic
energy of the bicyclist?
(1) 4.5 × 10^2 J (3) 5.4 × 10^3 J
(2) 9.0 × 10^2 J (4) 1.1 × 10^4 J

2 Answer

  • Kinetic E=1/2mv^2

    KE = 1/2 * 75 * 12^2 = 5400J = 5.4*10^3 J


  • Answer:

    (3) 5.4 × 10^3 J

    Explanation:

    The kinetic energy of the bicyclist can be calculated using the following equation:

    [tex]K=\frac{1}{2}mv^2[/tex]

    where

    m = 75 kg is the mass of the bicyclist

    v = 12 m/s is the speed of the byciclist

    By substituting these numbers into the equation, we find:

    [tex]K=\frac{1}{2}mv^2 = \frac{1}{2}(75 kg)(12 m/s)^2=5400 J=5.4 \cdot 10^3 J[/tex]

    So, the correct answer is

    (3) 5.4 × 10^3 J

NEWS TODAY