Mathematics

Question

A taxicab starts at (1, -2) on the grid. It goes 3 blocks east and 1 block south to pick up a passenger. Then it goes 6 blocks west and 5 blocks north and drops off the passenger. What are the coordinates of the point where the passenger was dropped off?
A taxicab starts at (1, -2) on the grid. It goes 3 blocks east and 1 block south to pick up a passenger. Then it goes 6 blocks west and 5 blocks north and drops

2 Answer

  • The coordinates of the point where the passenger was dropped of is the point (-2, 2).

    (1, -2) + (3, -1) = ((1 + 3), (-2 - 1)) = (4, -3)
    (4, -3) + (-6, 5) = ((4 - 6), (-3 + 5)) = (-2, 2)
  • Answer:  The co-ordinates of the point where the passenger was dropped are (-2, 2).

    Step-by-step explanation:  Given that a taxicab  starts at (1, -2) on the grid. It goes 3 blocks east and 1 block south to pick up a passenger.

    After that, it goes 6 blocks west and 5 blocks north and drops off the passenger.

    We are to find the coordinates of the point where the passenger was dropped off.

    3 blocks East:  When the taxicab goes 3 blocks east, then the the co-ordinates of the point becomes

    (1, -2)   ⇒   (1+3, -2) = (4, -2).

    1 block South:   When the taxicab goes 1 block South, then the the co-ordinates of the point becomes

    (4, -2)   ⇒   (4, -2-1) = (4, -3).

    6 blocks West:   When the taxicab goes 6 blocks West, then the the co-ordinates of the point becomes

    (4, -3)   ⇒   (4-6, -3) = (-2, -3).

    5 blocks North:   When the taxicab goes 5 blocks South, then the the co-ordinates of the point becomes

    (-2, -3)   ⇒   (-2, -3+5) = (-2, 2).

    Thus, the co-ordinates of the point where the passenger was dropped are (-2, 2).

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